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Proof step 3 from proof get-last-04 (previous step)

⊦ (a ' + x + y)[# x] = x.last, x = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
n ≠ 0 ⊦ (a ' + x)[(* n)] = x[n -1]
Proof step 5:
⊦ # x = 0, (x + y)[(# x)-1] = x.last, x = []

Rule argument

spec: <toplevel> name: get-numrec seq: n ≠ 0 ⊦ (a ' + x)[(* n)] = x[n -1] subst: [n, x, a] → [# x, x + y, a] flags: <all paths>

Additional information

Used simplifier rules: ⊦ # x = 0 ↔ x = []; (s) Used terms: # x, x + y, a