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Proof step 7 from proof get-last-04 (previous step)

# x = m + 1 ⊦ # x = 0, (x + y)[m] = x.last, x = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
# x = m + 1 ⊦ (x + y)[m] = x.last, x = []

Rule argument

Additional information

Used simplifier rules: ⊦ # x = 0 ↔ x = []; (s)