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Proof step 3 from proof lastN-append-01 (previous step)

n ≤ # y ⊦ lastn(n, x + y) = lastn(n, y)

User applied rule structural induction

And obtained the following new goals

Proof step 4:
n ≤ # y, ∀ n, y. n ≤ # y → lastn(n, x0 + y) = lastn(n, y) ⊦ lastn(n, (a + x0) + y) = lastn(n, y)

Rule argument

indvar: x

Additional information

Used simplifier rules: list freely generated by [], +;;% ⊦ [] + x = x; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list