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Proof step 3 from proof lastN-in-01 (previous step)

a ∈ lastn(n, x), n ≤ # x ⊦ a ∈ x

User applied rule structural induction

And obtained the following new goals

Proof step 4:
a ∈ lastn(n0 +1, x), n0 +1 ≤ # x, ∀ a, x. a ∈ lastn(n0, x) ∧ n0 ≤ # x → a ∈ x ⊦ a ∈ x

Rule argument

indvar: n

Additional information

Used simplifier rules: lastN-zero: ⊦ lastn(0, x) = [];%nat freely generated by 0, +1;;% ⊦ 0 ≤ m; (s)% ⊦ ¬ a ∈ []; (s)