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Proof step 4 from proof lastn-app (previous step)

n = n0 + # y, # y ≤ n ⊦ lastn(n, x + y) = lastn(n0, x) + y

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ lastn(n0 + # y, x + y) = lastn(n0, x) + y

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m ≤ m + n; (s)