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Proof step 2 from proof lastn-lastn (previous step)

∀ x. lastn(n0, lastn(n0, x)) = lastn(n0, x) ⊦ lastn(n0 +1, lastn(n0 +1, x)) = lastn(n0 +1, x)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
∀ x. lastn(n0, lastn(n0, x)) = lastn(n0, x) ⊦ lastn(n0 + 1, lastn(n0 + 1, x)) = lastn(n0 + 1, x)

Rule argument

Additional information

Used simplifier rules: ⊦ m +1 = m + 1; (s)