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Proof step 3 from proof lastn-mklist (previous step)

m ≤ n ⊦ lastn(m, mklist(a, n)) = mklist(a, m)

User applied rule structural induction

And obtained the following new goals

Proof step 4:
m ≤ n0 +1, ∀ m, a. m ≤ n0 → lastn(m, mklist(a, n0)) = mklist(a, m) ⊦ lastn(m, mklist(a, n0 +1)) = mklist(a, m)

Rule argument

indvar: n

Additional information

Used simplifier rules: lastN-zero: ⊦ lastn(0, x) = [];%nat freely generated by 0, +1;;% ⊦ mklist(a, 0) = []; (s)% ⊦ m ≤ 0 ↔ m = 0; (s)