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Proof step 1 from proof lastn-neq-04 (conclusion)
⊦ n ≤ # x ∧ b ∈ y ∧ ¬ b ∈ x → lastn(n, x) ≠ a ' + y
System applied rule normalize
And obtained the following new goals
Proof step 2
:
lastn(n, x) = a ' + y, b ∈ y, n ≤ # x ⊦ b ∈ x
Rule argument
Additional information