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Proof step 2 from proof lastn-restn-01 (previous step)

# x = n0 + n, n ≤ # x ⊦ lastn(n, x) = restn(n0, x)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
# x = n0 + n ⊦ lastn(n, x) = restn(n0, x)

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m ≤ m + n; (s)