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Proof step 5 from proof len-01 (previous step)

1 + # x0 < pos(a, a0 ' + x0), ∀ a. ¬ # x0 < pos(a, x0) ⊦

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 6:
1 + # x0 < pos(a, a0 ' + x0), ∀ a. ¬ # x0 < pos(a, x0) ⊦ a0 = a

Rule argument

fma: a0 = a

Additional information

Used simplifier rules: pos-y: ⊦ pos(a, a ' + x) = 0;%a: ⊦ (x + y) + z = x + y + z; from specification list%n0 < n ⊦ ¬ m + (* n) < (* n0); (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic Used formulas: a0 = a