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Proof step 2 from proof pos-equal (
previous step
)
pos(a, x) = n, a ∈ x ⊦ pos(b, x) = n ↔ a = b
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 3
:
pos(b, x) = pos(a, x), a ∈ x ⊦ a = b
Rule argument
Additional information