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Proof step 1 from proof pos-get-01 (conclusion)
⊦ ¬ dups(x) ∧ x[n] = a ∧ n < # x → pos(a, x) = n
System applied rule normalize
And obtained the following new goals
Proof step 2
:
x[n] = a, n < # x ⊦ pos(a, x) = n, dups(x)
Rule argument
Additional information