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Proof step 19 from proof put-at (previous step)

m0 < # x0, ∀ m, a, n. m < # x0 → x0[m, a][n] = x0[n] ∨ m = n ⊦ x0[m0, a][m1] = x0[m1], m0 = m1, x0 = []

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: m0, a, m1

Additional information

Used terms: m0, a, m1