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Proof step 20 from proof put-firstn-restn (previous step)

# y0 = m + 1, y0 = y0.butlast + y0.last ' ⊦ y0[m, a] = firstn(m, y0) + a ', y0 = []

User applied rule insert equation

And obtained the following new goals

Proof step 21:
#(y0.butlast + y0.last ') = m + 1, y0 = y0.butlast + y0.last ' ⊦ y0.butlast + y0.last ' = [], (y0.butlast + y0.last ')[m, a] = firstn(m, y0.butlast + y0.last ') + a '

Rule argument

pos: left 2 flags:

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