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Proof step 2 from proof restn-last (previous step)

n < # x ⊦ restn(n, x).last = x.last

User applied rule structural induction

And obtained the following new goals

Proof step 3:
n < #(a + x0), ∀ n. n < # x0 → restn(n, x0).last = x0.last ⊦ restn(n, a + x0).last = (a + x0).last

Rule argument

indvar: x

Additional information

Used simplifier rules: list freely generated by [], +;;% ⊦ # [] = 0; (s)% ⊦ ¬ n < 0; (s)