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Proof step 5 from proof restn-last (previous step)

n ≤ # x0, ∀ n. n < # x0 → restn(n, x0).last = x0.last ⊦ restn(n, a ' + x0).last = (a ' + x0).last, x0 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
n ≤ # x0, ∀ n. n < # x0 → restn(n, x0).last = x0.last ⊦ restn(n, a ' + x0).last = x0.last, x0 = []

Rule argument

Additional information

Used simplifier rules: a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ x ≠ [] → (a ' + x).last = x.last; (s)