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Proof step 2 from proof restn-size-last (previous step)

⊦ restn(# x, a ' + x) = (a ' + x).last ', x = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ restn(# x, a ' + x) = x.last ', x = []

Rule argument

Additional information

Used simplifier rules: a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ x ≠ [] → (a ' + x).last = x.last; (s)