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Proof step 11 from proof rmpos-get (previous step)

n < # x0, m1 < # x0, n ≤ m1, ∀ n0, m0. n0 + 1 < # x0 ∧ m0 < # x0 → (x0 -p m0)[n0] = (n0 < m0 ⊃ x0[n0];x0.tail[n0]) ⊦ (x0 -p m1)[n - # a '] = (a ' + x0)[n], x0 = [], n < # a '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
m1 < # x0, n < # x0, n ≤ m1, ∀ n0, m0. n0 + 1 < # x0 ∧ m0 < # x0 → (x0 -p m0)[n0] = (n0 < m0 ⊃ x0[n0];x0.tail[n0]) ⊦ (x0 -p m1)[n - 1] = (a ' + x0)[n], n = 0, x0 = []

Rule argument

Additional information

Used simplifier rules: ⊦ m < 1 ↔ m = 0; (s)% ⊦ # a ' = 0 +1; (s)