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Proof step 27 from proof rmpos-get (previous step)

m1 < # y, m < # y, m1 ≤ m, ∀ n, m0. n < # y ∧ ¬ # y < m0 → ((a ' + y) -p m0)[n] = (n < m0 ⊃ (a ' + y)[n];y[n]) ⊦ ((a ' + y) -p m1)[m] = y[m], y = []

Heuristic quantifier closing applied rule all left

And obtained the following new goals

Proof step 28:
m < # y, m1 < # y, m1 ≤ m, m1 < # y ∧ ¬ # y < m → ((a ' + y) -p m)[m1] = (m1 < m ⊃ (a ' + y)[m1];y[m1]), ∀ n, m0. n < # y ∧ ¬ # y < m0 → ((a ' + y) -p m0)[n] = (n < m0 ⊃ (a ' + y)[n];y[n]) ⊦ ((a ' + y) -p m1)[m] = y[m], y = []

Rule argument

pos: left 4 terms: m1, m

Additional information

Used terms: m1, m