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Proof step 5 from proof rmpos-get (previous step)

n < # x0, m ≤ # x0, ∀ n0, m0. n0 + 1 < # x0 ∧ m0 < # x0 → (x0 -p m0)[n0] = (n0 < m0 ⊃ x0[n0];x0.tail[n0]) ⊦ ((a ' + x0) -p m)[n] = (n < m ⊃ (a ' + x0)[n];x0[n]), x0 = []

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 6:
n < # x0, n < m, m ≤ # x0, ∀ n0, m0. n0 + 1 < # x0 ∧ m0 < # x0 → (x0 -p m0)[n0] = (n0 < m0 ⊃ x0[n0];x0.tail[n0]) ⊦ ((a ' + x0) -p m)[n] = (n < m ⊃ (a ' + x0)[n];x0[n]), x0 = []
Proof step 17:
n < # x0, m ≤ # x0, ∀ n0, m0. n0 + 1 < # x0 ∧ m0 < # x0 → (x0 -p m0)[n0] = (n0 < m0 ⊃ x0[n0];x0.tail[n0]) ⊦ ((a ' + x0) -p m)[n] = (n < m ⊃ (a ' + x0)[n];x0[n]), x0 = [], n < m

Rule argument

fma: n < m

Additional information

Used formulas: n < m