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Proof step 7 from proof size-del-nodups (previous step)

a ∈ x0, ∀ m0, a1. # x0 = m0 + 1 ∧ a1 ∈ x0 → #(x0 -l a1) = m0 ∨ x0 = [] ⊦ 1 + #(x0 -l a) = # x0, dups(x0), a0 ∈ x0

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 8:
a ∈ x0, ∀ m0, a1. # x0 = m0 + 1 ∧ a1 ∈ x0 → #(x0 -l a1) = m0 ∨ x0 = [] ⊦ 1 + #(x0 -l a) = # x0, x0 = [], dups(x0), a0 ∈ x0

Rule argument

fma: x0 = []

Additional information

Used simplifier rules: del-e: ⊦ [] -l a = [];% ⊦ # [] = 0; (s)% ⊦ ¬ a ∈ []; (s) Used formulas: x0 = []