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Proof step 3 from proof cons-03 (previous step)

disj(x, y) ⊦ disj(x + a ', y) ↔ ¬ a ∈ y

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 4:
disj(x, y), a ∈ y ⊦ disj(x + a ', y) ↔ ¬ a ∈ y
Proof step 9:
disj(x, y) ⊦ disj(x + a ', y) ↔ ¬ a ∈ y, a ∈ y

Rule argument

fma: a ∈ y

Additional information

Used formulas: a ∈ y