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Proof step 8 from proof cons-03 (previous step)

disj(x, y), a ∈ y, ∀ a0. ¬ a0 ∈ x ∧ a0 ≠ a ∨ ¬ a0 ∈ y ⊦

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: a

Additional information

Used terms: a