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Proof step 1 from proof eq-01 (conclusion)

⊦ x + a ' + b ' + y + c ' + z = x0 + a ' + c ' + z0 ∧ ¬ a ∈ y ∧ a ≠ b ∧ b ≠ c → dups(x + a ' + c ' + z)

System applied rule normalize

And obtained the following new goals

Proof step 2:
x + a ' + b ' + y + c ' + z = x0 + a ' + c ' + z0 ⊦ a = b, b = c, dups(x + a ' + c ' + z), a ∈ y

Rule argument

Additional information