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Proof step 1 from proof in-07 (conclusion)

⊦ ¬ dups(x + a ' + b ') → (dups(x + a ' + b ' + c ') ↔ a = c ∨ b = c ∨ c ∈ x)

System applied rule normalize

And obtained the following new goals

Proof step 2:
⊦ dups(x + a ' + b ' + c ') ↔ a = c ∨ b = c ∨ c ∈ x, dups(x + a ' + b ')

Rule argument

Additional information