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Proof step 1 from proof l-01 (conclusion)

⊦ a ≠ b ∧ ¬ b ∈ x → (dups(x + a ' + b ') ↔ dups(x + a '))

System applied rule normalize

And obtained the following new goals

Proof step 2:
⊦ dups(x + a ' + b ') ↔ dups(x + a '), a = b, b ∈ x

Rule argument

Additional information