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Proof step 9 from proof rec (previous step)

∃ y, z. x = y + (a + z) ⊦ ∃ a0, x0, y, z. a ' + x = x0 + a0 ' + y + a0 ' + z

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
⊦ ∃ a0, x, y0, z0. a ' + y + a ' + z = x + a0 ' + y0 + a0 ' + z0

Rule argument

Additional information

Used simplifier rules: ⊦ a + x = a ' + x; (s)