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Proof step 3 from proof rm-empty (previous step)

rmdup(a + x0) = [], rmdup(x0) = [] → x0 = [] ⊦ a + x0 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
rmdup(a ' + x0) = [] ⊦ rmdup(x0) = [], x0 = []

Rule argument

Additional information

Used simplifier rules: rm-one: ⊦ rmdup(a ') = a ';% ⊦ a ' ≠ []; (s)% ⊦ x + [] = x; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ a ' + x ≠ []; (s)% ⊦ a + x = a ' + x; (s)