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Proof step 2 from proof rm-in (previous step)

⊦ a ∈ rmdup([] + y) ↔ a ∈ [] ∨ a ∈ y

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ a ∈ rmdup(y) ↔ a ∈ y

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ a ∈ []; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ [] + x = x; (s)