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Proof step 5 from proof rm-notin (previous step)

a ∈ rmdup(a0 ' + x0), ∀ a. a ∈ rmdup(x0) → a ∈ x0 ⊦ a = a0, a ∈ x0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: a

Additional information

Used simplifier rules: rm-in: ⊦ a ∈ rmdup(x + y) ↔ a ∈ x ∨ a ∈ y;% ⊦ a ∈ b ' ↔ a = b; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list Used terms: a