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Proof step 2 from proof b-01 (previous step)

⊦ x.butlast = [] ↔ x = x.head ', x = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
x = x.last ' ⊦ x = [], x = x.head '

Rule argument

Additional information

Used simplifier rules: blapp: ⊦ x ≠ [] → (x.butlast = y ↔ x = y + x.last ');%l-06: ⊦ x = x.head ' → x.last = x.head;%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ [] + x = x; (s)