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Proof step 2 from proof bc (previous step)

⊦ (a ' + x).butlast = a ' + x.butlast, x = []

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: bapp: ⊦ y ≠ [] → (x + y).butlast = x + y.butlast;% ⊦ x + y = x + z ↔ y = z; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list