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Proof step 1 from proof bl (conclusion)

⊦ (a ' + x).butlast + (a ' + x).last ' + y = a ' + x + y

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ (a ' + x).butlast + (a ' + x).last ' = a ' + x

Rule argument

Additional information

Used simplifier rules: a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ x + y = z + y ↔ x = z; (s)