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Proof step 2 from proof blast-head (previous step)

a ∈ x.butlast ⊦ x.butlast.head = x.head, x = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
a ∈ x.butlast, a ∈ x ⊦ x.butlast.head = x.head, x = []

Rule argument

Additional information

Used simplifier rules: bin-01: x ≠ [] ⊦ a ∈ x.butlast → a ∈ x;