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Proof step 12 from proof blastN-rec-01 (previous step)

n ≤ # y + 1, ∀ x0, n, a. # x0 < #(y + a0 ') → n ≤ # x0 → butlastn(n, a ' + x0) = a ' + butlastn(n, x0) ⊦ butlastn(n -1, a ' + y) = a ' + butlastn(n, y + a0 '), n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
n ≤ # y + 1, ∀ x0, n, a. # x0 < #(y + a0 ') → n ≤ # x0 → butlastn(n, a ' + x0) = a ' + butlastn(n, x0) ⊦ butlastn(n - 1, a ' + y) = a ' + butlastn(n, y + a0 '), n = 0

Rule argument

Additional information

Used simplifier rules: ⊦ n -1 = n - 1; (s)