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Proof step 7 from proof blastN-rec-01 (previous step)

n ≤ # x, x ≠ [] → x = y + a0 ', ∀ x0, n, a. # x0 < # x → n ≤ # x0 → butlastn(n, a ' + x0) = a ' + butlastn(n, x0) ⊦ butlastn(n, a ' + x) = a ' + butlastn(n, x)

User applied rule cut formula

And obtained the following new goals

Proof step 8:
n ≤ # x, x ≠ [] → x = y + a0 ', ∀ x0, n, a. # x0 < # x → n ≤ # x0 → butlastn(n, a ' + x0) = a ' + butlastn(n, x0) ⊦ butlastn(n, a ' + x) = a ' + butlastn(n, x), x = []

Rule argument

fma: x = []

Additional information

Used simplifier rules: butlastN-base: ⊦ butlastn(0, x) = x;% ⊦ x + [] = x; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ # [] = 0; (s)% ⊦ m ≤ 0 ↔ m = 0; (s)% ⊦ a ' = b ' ↔ a = b; (s) Used formulas: x = []