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Proof step 3 from proof butlast-last (previous step)

⊦ x.butlast + x.last ' = x, x = []

User applied rule insert elim lemma

And obtained the following new goals

Proof step 4:
x ≠ [] ⊦ a = x.last ∧ y = x.butlast ↔ x = y + a '

Rule argument

spec: <toplevel> name: last-elim seq: x ≠ [] ⊦ a = x.last ∧ y = x.butlast ↔ x = y + a ' subst: [x, a, y] → [x, a, y]

Additional information

Used terms: x, a, y