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Proof step 14 from proof last-elim (previous step)

a = (a1 ' + x).last, a3 = a0, y1 = (a1 ' + x).butlast, ∀ a2, y0. a2 = (a1 ' + x).last ∧ y0 = (a1 ' + x).butlast ↔ a1 ' + x = y0 + a2 ' ⊦ a0 = a3 ∧ a1 ' + x = y1 + a '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
∀ a2, y0. a2 = (a1 ' + x).last ∧ y0 = (a1 ' + x).butlast ↔ a1 ' + x = y0 + a2 ' ⊦ a1 ' + x = (a1 ' + x).butlast + (a1 ' + x).last '

Proof step 14 from proof last-elim (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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