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Proof step 2 from proof last (previous step)

⊦ x.butlast + x.last = x, x = []

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: butlast-last: x ≠ [] ⊦ x.butlast + x.last ' = x;%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ x + a = x + a '; (s)