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Proof step 4 from proof mk-last-01 (previous step)

∀ a. mklist(a, m0).last = a ∨ m0 = 0 ⊦ m0 +1 = 0, mklist(a, m0 +1).last = a

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
∀ a. mklist(a, m0).last = a ⊦ (a ' + mklist(a, m0)).last = a, m0 = 0

Rule argument

Additional information

Used simplifier rules: mk-plus: ⊦ mklist(a, m + n) = mklist(a, m) + mklist(a, n);%mklist-one: ⊦ mklist(a, 1) = a ';%mk-last: ⊦ mklist(a, n) + a ' = a ' + mklist(a, n);%mk-zero: ⊦ mklist(a, 0) = [];%last-one: ⊦ a '.last = a;% ⊦ x + [] = x; (s)% ⊦ m + 1 ≠ 0; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ m +1 = m + 1; (s)