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Proof step 2 from proof mk-one (previous step)

⊦ mklist(a, m) + x = a ' ↔ m = 1 ∧ x = [], m = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
mklist(a, m) + x = a ' ⊦ m = 0, m = 1 ∧ x = []

Rule argument

Additional information

Used simplifier rules: mklist-one: ⊦ mklist(a, 1) = a ';% ⊦ a ' = b ' ↔ a = b; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ x + [] = x; (s)