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Proof step 3 from proof mk-tail-01 (previous step)

⊦ (mklist(a, m) + x).tail = mklist(a, m - 1) + x, m = 0

Heuristic elimination applied rule insert elim lemma

And closed the goal!

Rule argument

spec: nat name: elim-pred-c seq: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 subst: [n, m] → [m, m0]

Additional information

Used simplifier rules: mk-plus: ⊦ mklist(a, m + n) = mklist(a, m) + mklist(a, n);%mklist-one: ⊦ mklist(a, 1) = a ';%mk-last: ⊦ mklist(a, n) + a ' = a ' + mklist(a, n);% ⊦ m + 1 ≠ 0; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ (a ' + x).tail = x; (s)% ⊦ x + y = x + z ↔ y = z; (s)%n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1; (elim) Used terms: m, m0