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Proof step 19 from proof nodups-butlastn (previous step)

a ∈ butlastn(n, a0 ' + x), n ≤ 1 + # x, ∀ a, n. a ∈ butlastn(n, x) ∧ n ≤ # x → a ∈ x ⊦ a = a0, a ∈ x

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 20:
⊦ n ≤ # x → butlastn(n, a ' + x) = a ' + butlastn(n, x)
Proof step 21:
a ∈ butlastn(n, a0 ' + x), n ≤ 1 + # x, ∀ a, n. a ∈ butlastn(n, x) ∧ n ≤ # x → a ∈ x ⊦ a = a0, a ∈ x, n ≤ # x
Proof step 27:
a ∈ a0 ' + butlastn(n, x), n ≤ 1 + # x, n ≤ # x, ∀ a, n. a ∈ butlastn(n, x) ∧ n ≤ # x → a ∈ x ⊦ a = a0, a ∈ x

Rule argument

spec: <toplevel> name: blastN-rec-01 seq: ⊦ n ≤ # x → butlastn(n, a ' + x) = a ' + butlastn(n, x) subst: [x, a, n] → [x, a0, n] flags: <all paths>

Additional information

Used terms: x, a0, n