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Proof step 29 from proof nodups-butlastn (previous step)

n ≤ 1 + # x0, n ≤ # x0, ∀ n0. ¬ dups(butlastn(n0, x0)) ∨ ¬ n0 ≤ # x0, a ∈ butlastn(n, x0) ∨ dups(butlastn(n, x0)) ⊦ dups(x0), a ∈ x0, a ∈ butlastn(n, x0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
dups(butlastn(n, x0)), n ≤ # x0, n ≤ 1 + # x0, ∀ n0. ¬ dups(butlastn(n0, x0)) ∨ ¬ n0 ≤ # x0 ⊦ dups(x0), a ∈ butlastn(n, x0), a ∈ x0

Proof step 29 from proof nodups-butlastn (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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