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Proof step 2 from proof prefix-butlast-append (previous step)

⊦ x ⊑ x.butlast + a ' ↔ a = x.last, x = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
x ⊑ x.butlast + a ' ⊦ a = x.last, x = []

Rule argument

Additional information

Used simplifier rules: butlast-last: x ≠ [] ⊦ x.butlast + x.last ' = x;%prefix-self: ⊦ x ⊑ x;%a: ⊦ (x + y) + z = x + y + z; from specification list