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Proof step 1 from proof rev-disjoint (conclusion)

⊦ disj(x, rev(y)) ↔ disj(x, y)

Heuristic structural induction applied rule structural induction

And obtained the following new goals

Proof step 2:
∀ x. disj(x, rev(y0)) ↔ disj(x, y0) ⊦ disj(x, rev(a + y0)) ↔ disj(x, a + y0)

Rule argument

term: y

Additional information

Used simplifier rules: rev-e: ⊦ rev([]) = [];%list freely generated by [], +;;% ⊦ disj(x, []); (s)