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Proof step 1 from proof rev-length (conclusion)

⊦ # rev(x) = # x

Heuristic structural induction applied rule structural induction

And closed the goal!

Rule argument

term: x

Additional information

Used simplifier rules: rev-e: ⊦ rev([]) = [];%rev-r: ⊦ rev(a ' + x) = rev(x) + a;%list freely generated by [], +;;% ⊦ a + x = a ' + x; (s)% ⊦ x + a = x + a '; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ #(x + y) = # x + # y; (s)% ⊦ # a ' = 0 +1; (s)% ⊦ m + n = m + n0 ↔ n = n0; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic% ⊦ # [] = 0; (s)