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Proof step 2 from proof splitlasteq-01 (previous step)

⊦ y = x + a ' ↔ x = y.butlast ∧ a = y.last, y = []

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: butlast-def: ⊦ (x + a ').butlast = x;%last-def: ⊦ (x + a ').last = a;%blapp: ⊦ x ≠ [] → (x.butlast = y ↔ x = y + x.last ');%a: ⊦ (x + y) + z = x + y + z; from specification list