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Proof step 5 from proof del1-01 (previous step)

∀ a, b. #oc(a, x0 -1l b) = #oc(a, x0) ∨ a = b ⊦ #oc(a, (a0 ' + x0) -1l b) = #oc(a, a0 ') + #oc(a, x0), a = b

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 6:
a0 = a, ∀ a, b. #oc(a, x0 -1l b) = #oc(a, x0) ∨ a = b ⊦ #oc(a, (a0 ' + x0) -1l b) = #oc(a, a0 ') + #oc(a, x0), a = b
Proof step 8:
∀ a, b. #oc(a, x0 -1l b) = #oc(a, x0) ∨ a = b ⊦ #oc(a, (a0 ' + x0) -1l b) = #oc(a, a0 ') + #oc(a, x0), a = b, a0 = a

Rule argument

fma: a0 = a

Additional information

Used formulas: a0 = a