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Proof step 2 from proof in-02 (previous step)

perm(a ' + x, b ' + y) ⊦ a = b, a ∈ y

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: rec: ⊦ a ≠ b → (perm(a ' + x, b ' + y) ↔ a ∈ y ∧ b ∈ x ∧ perm(x -1l b, y -1l a));%a: ⊦ (x + y) + z = x + y + z; from specification list